bonjour, pouvez vous m aider s'il vous plaît. ​

Réponse :

Explications étape par étape :

Bonjour

on calcule les 5 premiers termes de chaque suite

Un = 4n² - 2n + 6

u₀= 4(0)² - 2(0) + 6 = 6

u₁ = 4(1)² - 2(1) + 6 = 4 - 2 + 6 = 8

u₂= 4(2)² - 2(2) + 6 =  16 - 4 + 6 = 18

u₃= 4(3)² - 2(3) + 6 = 36 - 6 + 6 = 36

u₄ = 4(4)² - 2(4) + 6 = 64 - 8 + 6 = 62

Vn = (n + 3) /(n + 1)

v₀ =  ( 0 + 3) /( 0 + 1) = 3/1 = 3

v₁ = ( 1 + 3) /( 1 + 1) = 4/2 = 2

v₂ = ( 2 + 3) /( 2 + 1) = 5/3

v₃ = ( 3 + 3) /( 3 + 1) = 6/4

v₄ = ( 4 + 3) /( 4 + 1) = 7/5

Wn = 5n + 3/(n+ 2)

w₀ = 5(0) + 3/((0)+ 2) = 3/2

w₁ = 5(1) + 3/((1)+ 2) = 5 + 1 = 6

w₂= 5(2) + 3/((2)+ 2) = 10 + 3/4 = 43/4

w₃ = 5(3) + 3/((3)+ 2) = 15 + 3/5 = 78/5

w₄= 5(4) + 3/((4)+ 2) = 20 + 3/6 = 20 + 1/2 = 41/2

Tn = √(n + 6)

t₀ = √((0) + 6)= √6

t₁ = √((1) + 6)= √7

t₂= √((2) + 6)= √8

t₃= √((3) + 6)= √9 = 3

t₄= √((4) + 6)= √10

Up = p³ - 4p + 7

p₀= (0)³ - 4(0) + 7 = 7

p₁ = (1)³ - 4(1) + 7 = 1 - 4 + 7 = 4

p₂= (2)³ - 4(2) + 7 = 8 - 8 + 7 = 7

p₃ =(3)³ - 4(3) + 7 = 27 - 12 + 7 = 22

p₄= (4)³ - 4(4) + 7 = 64 - 16 + 7 = 55

Un = 4 × 3ⁿ

u₀ = 4 × 3⁰ = 4 × 1 = 4

u₁ = 4 × 3¹ = 4 × 3 = 12

u₂ =4 × 3² = 4 × 9 = 36

u₃ =4 × 3³ = 4 × 27 = 108

u₄ =4 × 3⁴ = 4 × 81 = 324

Un = 3/n + 2

u₁=  3/(1) + 2 = 3 + 2 = 5

u₂ = 3/(2) + 2 = 3/6 + 2 = 1/2 + 2 = 5/2

u₃ = 3/(3) + 2 = 1 + 2 = 3

u₄ = 3/(4) + 2 = 3/4 + 8/4 = 11/4

u₅ = 3/(5) + 2 = 3/5 + 10/5 = 13/5