Mathématiques

Question

Factoriser
R(x)=(2x+1)(3x-4)-(2x+1)(2x+3)
S(x)=(2x-3)(4x-5)-(4x^2-12x+9)

2 Réponse

  • Salut,
    R(x)=(2x+1)(3x-4)-(2x+1)(2x+3)
    R(x) = (2x+1)([3x - 4 - (2x+3)]
    R(x) = (2x+1)(3x - 4 - 2x - 3)
    R(x) = (2x+1)(x - 7)


    S(x)=(2x-3)(4x-5)-(4x^2-12x+9)

    S(x) = (2x-3)(4x-5) - (2x-3)²
    S(x) = (2x-3)(4x-5) - (2x-3)(2x-3)
    S(x) = (2x-3)[(4x-5)-(2x-3)]
    S(x) = (2x-3)(4x-5-2x+3)
    S(x) = (2x-3)(2x-2)
    ---> Niveau début 1ère : S(x) = 2(2x-3)(x-1)

    Bonne soirée !

  • R(x)=(2x+1)(3x-4)-(2x+1)(2x+3)
    r = (2x+1)(3x-4-2x-3)
    r = (2x+1)(x-7)

    S(x)=(2x-3)(4x-5)-(4x^2-12x+9)

    s = (2x-3)(4x-5) -(2x-3)²
    s =(2x-3)(4x-5-2x+3)
    s =(2x-3)(2x-2)

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