Mathématiques

Question

X²+ X - 6≥ 0, svp aidez moi​

1 Réponse

  • Bonjour

    X²+ X - 6≥ 0

    x^2 + 2 * x * 1/2 + (1/2)^2 - (1/2)^2 - 6 >> 0

    (x + 1/2)^2 - 1/4 - 24/4 >> 0

    (x + 1/2)^2 - 25/4 >> 0

    (x + 1/2)^2 - (5/2)^2 >> 0

    (x + 1/2 - 5/2)(x + 1/2 + 5/2) >> 0

    (x + 6/2)(x - 4/2) >> 0

    (x + 3)(x - 2) >> 0

    x + 3 = 0 ou x - 2 = 0

    x = -3 ou x = 2

    x……….|-inf………(-3)……..…2………..+inf

    x + 3….|……..(-)..…o……(+)…….(+)………

    x - 2…..|……..(-)………….(-)…o…..(+)………

    Ineq….|……..(+)…..o….(-)….o….(+)……..

    x € ]-inf ; -3] U [2 ; +inf [

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